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15 June, 11:22

Light of wavelength 575 nm falls on two double slits spaced 0.30 mm apart. What is the required distance from the slits to a screen if the spacing between the first and second dark fringe is to be 4.00 mm

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  1. 15 June, 11:43
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    L = 2.1 m

    Explanation:

    From Young's Double Slit Experiment, the formula for the distance between two consecutive dark or bright fringes, called fringe spacing, is derived as:

    Δx = λL/d

    where,

    Δx = distance between first and second dark fringe = 4 mm = 4 x 10⁻³ m

    λ = wavelength of light = 575 nm = 5.75 x 10⁻⁷ m

    d = distance between the slits = 0.3 mm = 3 x 10⁻⁴ m

    L = Distance from slits to screen = ?

    Therefore,

    4 x 10⁻³ m = (5.75 x 10⁻⁷ m) (L) / (3 x 10⁻⁴ m)

    L = (4 x 10⁻³ m) / (1.92 x 10⁻³)

    L = 2.1 m
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