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9 April, 09:59

A worker drives a 0.562 kg spike into a rail tie with a 2.26 kg sledgehammer. The hammer hits the spike with a speed of 64.4 m/s. If one third of the hammer's kinetic energy is converted to the internal energy of the hammer and spike, how much does the total internal energy increase? Answer in units of J

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  1. 9 April, 10:15
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    Given that,

    Mass of sledge hammer;

    Mh = 2.26 kg

    Hammer speed;

    Vh = 64.4 m/s

    The expression fot the kinetic energy of the hammer is,

    K. E (hammer) = ½Mh•Vh²

    K. E (hammer) = ½ * 2.26 * 64.4²

    K. E (hammer) = 4686.52 J

    If one forth of the kinetic energy is converted into internal energy, then

    ΔU = ¼ * K. E (hammer)

    ∆U = ¼ * 4686.52

    ∆U = 1171.63 J

    Thus, the increase in total internal energy will be 1171.63 J.
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