Ask Question
8 October, 04:28

Six new refrigerator prototypes are tested in the laboratory. For each refrigerator, the electrical power P needed for it to operate and the maximum heat energy that can be removed per second QC, max/Δt from its interior are given.

Part A

Rank these refrigerators on the basis of their performance coefficient.

Rank from largest to smallest. To rank items as equivalent, overlap them.

Part B

Thsee six refrigerators are placed in six identical sealed rooms. Rank the refrigerators on the basis of the rate at which they raise the temperature of the room.

Rank from largest to smallest. To rank items as equivalent, overlap them.

1) P = 750 W, Qc, max/deltaT = 1500 J/s

2) P = 400 W, Qc, max/deltaT = 1200 J/s

3) P = 500 W, Qc, max/deltaT = 2000 J/s

4) P = 250 W, Qc, max/deltaT = 1000 J/s

5) P = 500 W, Qc, max/deltaT = 1500 J/s

6) P = 1000 W, Qc, max/deltaT = 3000 J/s

+1
Answers (1)
  1. 8 October, 04:54
    0
    performance coefficient from largest to the smallest

    P = 500 W, Qc, max/deltaT = 2000 J/s

    P = 250 W, Qc, max/deltaT = 1000 J/s

    P = 750 W, Qc, max/deltaT = 1500 J/s

    ) P = 400 W, Qc, max/deltaT = 1200 J/s

    P = 500 W, Qc, max/deltaT = 1500 J/s

    P = 1000 W, Qc, max/deltaT = 3000 J/s.

    the rate at which they raise the temperature of the room.

    2.1. P = 1000 W, Qc, max/deltaT = 3000 J/s

    P = 500 W, Qc, max/deltaT = 2000 J/s

    P = 750 W, Qc, max/deltaT = 1500 J/s

    P = 500 W, Qc, max/deltaT = 1500 J/s

    P = 400 W, Qc, max/deltaT = 1200 J/s

    P = 250 W, Qc, max/deltaT = 1000 J/s

    Explanation:

    A refrigerator is a device that uses work to remove heat energy from a cold reservoir and deposit it into a hot reservoir ... A good refrigerator (with a large performance coefficient) will remove a large amount of heat energy from the cold reservoir for a small amount of work input

    The performance coefficient of a refrigerator is defined as the ratio of the heat energy removed from the cold reservoir to the work input to the refrigerator:

    k=QC/W

    power is defined as work per unit time

    1. k=1500/750=2

    2. 1200/400=3

    3.2000/500=4

    4.1000/250=4

    5.1500/500=3

    6.3000/1000=3

    performance coefficient from largest to the smallest

    P = 500 W, Qc, max/deltaT = 2000 J/s

    P = 250 W, Qc, max/deltaT = 1000 J/s

    P = 750 W, Qc, max/deltaT = 1500 J/s

    ) P = 400 W, Qc, max/deltaT = 1200 J/s

    P = 500 W, Qc, max/deltaT = 1500 J/s

    P = 1000 W, Qc, max/deltaT = 3000 J/s

    2, Rate at which they raise the temperature of the room.

    rate at which temperature rises in the inner chamber of the refrigerator is proportional to the rate of energy used to dispel heat from the refrigerator

    1. P = 1000 W, Qc, max/deltaT = 3000 J/s

    P = 500 W, Qc, max/deltaT = 2000 J/s

    P = 750 W, Qc, max/deltaT = 1500 J/s

    P = 500 W, Qc, max/deltaT = 1500 J/s

    P = 400 W, Qc, max/deltaT = 1200 J/s

    P = 250 W, Qc, max/deltaT = 1000 J/s
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Six new refrigerator prototypes are tested in the laboratory. For each refrigerator, the electrical power P needed for it to operate and ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers