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7 August, 15:32

The amount of internal energy needed to raise the temperature of 0.25 kg of water by 0.2°C is 209.3 J. How fast must a 0.25 kg baseball travel in order for its kinetic energy to equal this internal energy?

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  1. 7 August, 15:57
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    The baseball must be 40.92 m/s fast

    Explanation:

    Kinetic Energy: This maybe defined as the energy of a body, due to motion.

    The S. I unit of kinetic energy is Joules (J)

    Kinetic Energy is represented as

    Ek = 1/2mv² ... Equation 1

    making v the subject of the equation,

    v = √ (2Ek/m) ... Equation 2

    Ek = Kinetic Energy of the base ball, m = mass of the base ball, v = velocity of the base ball.

    Given: m = 0.25 kg, Ek = 209.3 J,

    Note: The Kinetic energy of the baseball is equal to the internal energy of water.

    Substituting these values into equation 2

    v = √ (2*209.3/0.25)

    v = √1674.4

    v = 40.92 m/s

    Thus the baseball must be 40.92 m/s fast
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