An object is dropped near the surface of a planet such that the gravitational field at the object's location is 8 Nkg. If the object is thrown upward at a speed of 20 ms, what is the position of the object in relation to the position in which the object was released and thrown upward after 3s?

A - 96 m below the release position

B - 36 m below the release position

C-15 m above the release position

D - 24 m above the release position

Question

John Moses

Physics

28 October, 11:58

An object is dropped near the surface of a planet such that the gravitational field at the object's location is 8 Nkg. If the object is thrown upward at a speed of 20 ms, what is the position of the object in relation to the position in which the object was released and thrown upward after 3s?

A - 96 m below the release position

B - 36 m below the release position

C-15 m above the release position

D - 24 m above the release position

+5

Answers (1)

Know the Answer?

Ronald Pierce · Answer 1

D - 24 m above the release position

Explanation:

Given:

v₀ = 20 m/s

a = - 8 m/s²

t = 3 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (20 m/s) (3 s) + ½ (-8 m/s²) (3 s) ²

Δx = 24 m