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2 July, 09:37

Astronauts on the first trip to mars take along a pendulum that has a period on earth of 1.09 s. the period on the other planet turns out to be 3.23 s. what is the free-fall acceleration on that other planet?

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  1. 2 July, 09:52
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    Not sure exactly. I am not sure what this
  2. 2 July, 09:57
    0
    T=2pi * sqrt (l/g)

    1.09=2*3.14*sqrt (l/9.8)

    => l=0.295

    3.23=2*3.14 * sqrt (0.295/gg)

    => gg=1.116
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