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10 January, 16:58

Focus on Concepts, Question 06 A 1650-kg car is traveling at 38.1 m/s. How fast must a 91.0-kg bicycle and rider be traveling to have the same kinetic energy as the car?

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  1. 10 January, 17:00
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    162.24 m/s

    Explanation:

    The kinetic energy of the car is given as:

    KE = ½ * m * v²

    Where m = mass of car

    v = velocity of car

    = ½ * 1650 * 38.1²

    = 1197578.3 J

    For the bicycle to have the same KE, then:

    1197578.3 = ½ * M * V²

    Where M = Mass of bicycle

    V = velocity of bicycle

    1197578.3 = ½ * 91 * V²

    V² = 1197578.3 / (91 * ½)

    V² = 26320.4

    V = 162.24 m/s

    The bicycle will have to move at 162.24 m/s to have the same Kinetic energy as the car.
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