Ask Question
7 November, 21:21

A rock is suspended by a light string. When the rock is in air, the tension in the string is 39.2 N. When the rock is totally immersed in water, the tension is 28.4 N. When the rock is totally immersed in an unknown liquid, the tension is 18.6 N. What is the Density of the unknown liquid. - When I looked at this problem, I though we needed to know the volume of the rock. Can someone show me how to do it without the volume of this rock?

+2
Answers (1)
  1. 7 November, 21:45
    0
    1.1 g/cm^3

    Explanation:

    weight in air, Wa = 39.2 N

    weight in water, Ww = 28.4 N

    weight in liquid, Wl = 18.6 N

    Let d be the density of unknown liquid.

    By using the formula of relative density

    relative density of unknown liquid

    = (wt. in air - wt. in water) / (wt. in water - wt. in liquid)

    d = (Wa - Ww) / (Ww - Wl)

    d = (39.2 - 28.4) / (28.4 - 18.6)

    d = 10.8 / 9.8

    d = 1.1

    Thus, the density of unknown liquid is 1.1 g/cm^3.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A rock is suspended by a light string. When the rock is in air, the tension in the string is 39.2 N. When the rock is totally immersed in ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers