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23 December, 02:00

A 2000 kg car experiences a constant braking

force of 10,000 N, and comes to be a stop in 6

sec.

What would be the distance traveled by the

car in coming to rest?

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Answers (1)
  1. 23 December, 02:07
    0
    Solving for acceleration:

    F = ma

    10000 = 2000*a

    a = 5 m/s^2

    Solving for velocity:

    Vf = Vi + a (t)

    0 = Vi - (5) (6)

    Vi = 30 m/s

    Solving for displacement or distance:

    S = Vi*t - 1/2 * a * t^2

    S = 30 (6) - 1/2 (5) (6) ^2

    S = 90m

    The car would have traveled 90m before coming to rest.
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