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1 July, 14:29

Two flat conductors are placed with their inner faces separated by 8 mm. If the surface charge density on one of the inner faces is 33 pC/m2 and the other inner face - 33 pC/m2, what is the magnitude of the electric potential difference between the two conductors? Answer in units of V

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  1. 1 July, 14:48
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    = 0.0298V

    Explanation:

    Electric field between two conductor = σ / ε₀

    σ = 33pC/m²

    = 33 * 10⁻¹²C/m²

    ε₀ = 8.85 * 10 ⁻¹²C²/Nm²

    E = 33 * 10⁻¹² / 8.85 * 10 ⁻¹²

    = 3.7288N/C

    potential difference between two conductors = Ed

    where d = 8mm = 8 * 10 ⁻³m

    V = 3.7288 * 8 * 10 ⁻³

    = 29.83 * 10 ⁻³

    = 0.0298V
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