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25 January, 07:48

A very strong, but inept, shot putter puts the shot straight up vertically with an initial velocity of 11.0 m/s. how long does he have to get out of the way?

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  1. 25 January, 09:39
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    The shot putter should get out of the way before the ball returns to the launch position.

    Assume that the launch height is the reference height of zero.

    u = 11.0 m/s, upward launch velocity.

    g = 9.8 m/s², acceleration due to gravity.

    The time when the ball is at the reference position (of zero) is given by

    ut - (1/2) gt² = 0

    11t - 0.5*9.8t² = 0

    t (11 - 4.9t) = 0

    t = 0 or t = 4.9/11 = 0.45 s

    t = 0 corresponds to when the ball is launched.

    t = 0.45 corresponds to when the ball returns to the launch position.

    Answer: 0.45 s
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