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4 May, 18:13

A boy jumps from rest, straight down from the top of a cliff. He falls halfway down to the water below in 0.866 s. How much time passes during his entire trip from the top down to the water? Ignore air resistance.

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  1. 4 May, 18:21
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    Entire trip takes 1.22 seconds.

    Explanation:

    We have equation of motion s = ut + 0.5 at²

    Initial velocity, u = 0 m/s

    Acceleration, a = 9.81 m/s²

    Time, t = 0.866 s

    Substituting

    s = ut + 0.5 at²

    s = 0 x 0.866 + 0.5 x 9.81 x 0.866²

    s = 3.68 m

    Halfway is 3.68 m

    Total height = 2 x 3.68 = 7.36 m

    We have equation of motion s = ut + 0.5 at²

    Initial velocity, u = 0 m/s

    Acceleration, a = 9.81 m/s²

    Time, t = ?

    Displacement, s = 7.36 m

    Substituting

    s = ut + 0.5 at²

    7.36 = 0 x t + 0.5 x 9.81 x t²

    t = 1.22 s

    Entire trip takes 1.22 seconds.
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