Suppose that you charge a 5 F capacitor in a circuit containing nine 4.5 V batteries, so the final potential difference across the plates is 40.5 V. How much charge is on each plate

The charge is on each plate is 202.5 C

Explanation:

Given;

capacitance, C = 5 F

voltage of each battery = 4.5 V

total potential across the plates, V = 40.5 V

From the total potential given, it can be concluded that the circuit is in series. The charge on each plate is the same.

Q = CV

Where;

Q is the charge on each plate

C is the capacitance

V is the total potential across the plates

Q = 5 x 40.5

Q = 202.5 C

Therefore, the charge is on each plate is 202.5 C