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2 May, 16:07

A discus thrower accelerates a discus from rest to a speed of 25.4 m/s by whirling it through 1.21 rev. Assume the discus moves on the arc of a circle 0.95 m in radius. A discus thrower moving in a circle as he prepares to throw the discus. (a) Calculate the final angular speed of the discus. rad/s (b) Determine the magnitude of the angular acceleration of the discus, assuming it to be constant. rad/s2 (c) Calculate the time interval required for the discus to accelerate from rest to 25.4 m/s. s

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  1. 2 May, 16:26
    0
    Given:

    vo = 0

    v = 25.4 m/s

    r = 0.95 m

    n = 1.21 rev

    A.

    r*ω = v

    ω = v/r

    = 25.4/.95

    = 26.74 rad/s

    B.

    θ = 2πn

    = 2π * (1.21)

    = 7.6 m

    Using equation of motion,

    ωf^2 = ωi^2 + 2αθ

    (26.74) ^2 = 2 * α * (7.6)

    α = 715.03/15.2

    = 47.04 rad/s^2

    C.

    Using equation of motion,

    θ = ωi*t + 1/2*α*t^2

    θ = 0 + 1/2*α*t^2

    7.6 = 47.04/2 * t^2

    = sqrt (0.323)

    = 0.57 s
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