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14 August, 22:58

A 16-Ω loudspeaker, an 8.0-Ω loudspeaker, and a 4.0-Ω loudspeaker are connected in parallel across the terminals of an amplifier. Determine the equivalent resistance of the three speakers, assuming that they all behave as resistors.

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  1. 14 August, 23:01
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    2.286 ohm

    Explanation:

    R1 = 16 ohm

    R2 = 8 ohm

    R3 = 4 ohm

    They all are connected in parallel combination

    Let the equivalent resistance is R.

    1/R = 1/R1 + 1/R2 + 1/R3

    1/R = 1/16 + 1/8 + 1/4

    1/R = (1 + 2 + 4) / 16

    1/R = 7 / 16

    R = 16/7 = 2.286 ohm
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