A 95 N force exerted at the end of a 0.50 m long torque wrench gives rise to a torque of 15 Nm. What is the angel (assumed to be less than 90 degrees) between the wrench handle and the direction the force is applied?

Question

Daniel Kemp

Physics

21 October, 17:26

A 95 N force exerted at the end of a 0.50 m long torque wrench gives rise to a torque of 15 Nm. What is the angel (assumed to be less than 90 degrees) between the wrench handle and the direction the force is applied?

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Answers (1)

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Luciana Santiago · Answer 1

9.1°

Explanation:

Torque = distance from pivot * perpendicular force

15 Nm = 0.5 m * perpendicular force

perpendicular force = 30 N

So the bertical component of the applied force that caused a turning effect (torque) was 30 N. Now we use this information to find the angle that would produce a vertical component of 30N from an applied force of 95 N.

Fy = FSinθ

15 = 95 Sinθ

θ = 9.1°