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5 December, 08:49

How much amount of heat is required to raise the temperature of 20 grams of water from 10°C to 30°C? The specific heat of water is 4.18 J/g°C.

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  1. 5 December, 08:58
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    The amount of heat:

    Q = m c ΔT

    m = 20 g, c = 4.18 J/g°C, ΔT = 30° - 10° = 20° C

    Q = 20 g · 4.18 J/g°C · 20°C = 1672 J

    Answer: C) 1700 J
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