A particle (mass = 5.0 g, charge = 40 mC) moves in a region of space where the electric field is uniform and is given by Ex = - 2.3 N/C, Ey = Ez = 0. If the position and velocity of the particle at t = 0 are given by x = y = z = 0 and vz = 20 m/s, vx = vy = 0, what is the distance from the origin to the particle at t = 2.0 s?

Question

Cael Wright

Physics

23 August, 12:08

A particle (mass = 5.0 g, charge = 40 mC) moves in a region of space where the electric field is uniform and is given by Ex = - 2.3 N/C, Ey = Ez = 0. If the position and velocity of the particle at t = 0 are given by x = y = z = 0 and vz = 20 m/s, vx = vy = 0, what is the distance from the origin to the particle at t = 2.0 s?

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Savion Duncan · Answer 1

Answer: 40m

Explanation: Distance is a function of speed / velocity and time.

From the question the velocity along the z axis is given as 20 m/s at t = 0 secs We were ask to calculate the distance travelled when t = 2secs.

Recall that,

Velocity = distance travelled / time

Since we're calculating for distance we make it subject of formula;

Distance travelled = velocity * time

= 20m/s * 2s

= 40meter.