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17 April, 04:18

The length of a retanle is twice the width plus 10. if the perimenter of the rectangle must be 200 inches what is the maimumarea of the rectange?

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  1. 17 April, 04:39
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    Area = 2100 inch²

    Explanation:

    The length of a rectangle is twice the width plus 10

    Let L be the length and W be the width.

    L = 2W + 10

    The perimeter of the rectangle must be 200 inches

    Perimeter = 2 (L+W) = 200

    2 (2W+10+W) = 200

    3W + 10 = 100

    3W = 90

    W = 30 inches

    L = 2 x 30 + 10 = 70 inches

    Area = Length x Width

    Area = 30 x 70

    Area = 2100 inch²
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