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18 March, 02:30

A box slides down a 30.0° ramp with an acceleration of 1.20 m/s^2. Determine the coefficient of kinetic friction between the box and the ramp.

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  1. 18 March, 02:58
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    m = mass of the box

    N = normal force on the box

    f = kinetic frictional force on the box

    a = acceleration of the box

    μ = coefficient of kinetic friction

    perpendicular to incline, force equation is given as

    N = mg Cos30 eq-1

    kinetic frictional force is given as

    f = μ N

    using eq-1

    f = μ mg Cos30

    parallel to incline, force equation is given as

    mg Sin30 - f = ma

    mg Sin30 - μ mg Cos30 = ma

    "m" cancel out

    a = g Sin30 - μ g Cos30

    inserting the values

    1.20 = (9.8) Sin30 - (9.8) Cos30 μ

    μ = 0.44
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