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12 March, 06:55

You are driving down the highway late one night at 20 m/s when a deer steps onto the road 35 m in front of you. Your reaction time before stepping on the brakes is 0.50 s, and the maximum deceleration of your car is 10 m/s2. How much distance is between you and the deer when you come to a stop?

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  1. 12 March, 07:08
    0
    A) Mind you before your reaction time, you had be going at a uniform speed 20m/s so for the reaction time of 0.5 seconds, you had covered a distance of:

    20m/s*0.5s = 10 m

    For the second part which involved deceleration, using:

    v = u - at, Noting that there is deceleration.

    u = 20m/s, v = final velocity = 0, a = - 10m/s².

    Let us solve for the time.

    v = u + at

    0 = 20 - 10*t

    10t = 20

    t = 20/10 = 2 seconds.

    Let us compute for the distance covered during the 2s

    s = ut + 1/2at², a = - 10 m/s²

    s = 20*2 - 0.5*10*2² = 20m

    So the total distance covered = Distance covered from reaction time + Distance covered from deceleration

    = 10m + 20m = 30m

    So you have covered 30m out of the initial 35m.

    Distance between you and the dear: 35 - 30 = 5m

    So you have 5m between you and the deer. So you did not hit the deer.
  2. 12 March, 07:25
    0
    So the dear is 35m away from the car that is running at a speed of 20m/s where your reaction time in hitting the brakes is 0.5s and the cars deceleration is 10 m/s2. By calculating i came up with an answer of 5meters, the car only have 5 meters away from the deer to hit it.
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