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24 December, 15:29

A skateboarder starts at 2.75 m/s and accelerates for 8.90 s over a distance of 16.7

m. What is his final velocity?

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Answers (1)
  1. 24 December, 15:41
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    1.00 m/s

    Explanation:

    Given:

    Δx = 16.7 m

    v₀ = 2.75 m/s

    t = 8.90 s

    Find: v

    Δx = ½ (v + v₀) t

    16.7 m = ½ (v + 2.75 m/s) (8.90 s)

    v = 1.00 m/s
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