A 6 kg box has a coefficient of friction with a table of 0.7, and it's slowing down across the table with no pushing force. What is the acceleration of the box?

A. 42 m/s^2

B. 7 m/s^2

C. 6 m/s^2

D. 0.7 m/s^2

Question

Jair Graves

Physics

2 January, 04:08

A 6 kg box has a coefficient of friction with a table of 0.7, and it's slowing down across the table with no pushing force. What is the acceleration of the box?

A. 42 m/s^2

B. 7 m/s^2

C. 6 m/s^2

D. 0.7 m/s^2

+1

Answers (1)

Know the Answer?

Clare · Answer 1

B. 7 m/s²

Explanation:

Draw a free body diagram of the box. There are three forces:

Normal force N pushing up.

Weight force mg pulling down.

Friction force Nμ pushing against the direction of motion.

Sum of forces in the y direction:

∑F = ma

N - mg = 0

N = mg

Sum of forces in the x direction:

∑F = ma

-Nμ = ma

-mgμ = ma

a = - gμ

a = - (9.8 m/s²) (0.7)

a ≈ - 7 m/s²

The magnitude of the box's acceleration is 7 m/s².

A 6 kg box has a coefficient of friction with a table of 0.7, and it's slowing down across the table with no pushing force. What is the acceleration of the box?A. 42 m/s^2B. 7 m/s^2C. 6 m/s^2D. 0.7 m/s^2

A 6 kg box has a coefficient of friction with a table of 0.7, and it's slowing down across the table with no pushing force. What is the acceleration of the box?

A. 42 m/s^2

B. 7 m/s^2

C. 6 m/s^2

D. 0.7 m/s^2