A golfer hits a golf ball with a velocity of 36.0 meters/second at an angle of 28.0°. If the hang time of the golf ball is 3.44 seconds, what is the range of the golf ball?

Solving this using the time, we know that range = horizontal velocity x time of flight

since there are no horizontal forces acting on the ball, there are no horizontal accelerations and the initial horizontal velocity of 36 cos 28 will be constant throughout. I f we use the correct time of flight given the launch parameters, we have

range = 36 cos 28 x 3.44 s = 109.3 m