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24 October, 21:04

the car is moving on a straight road at a speed of 15m / s. The driver of the car starts overtaking with an acceleration of 2m / s². Determine how fast the car has reached after 6s from the start of overtaking. The speed at uniformly accelerated rectilinear motion with the initial speed is calculated by the formula v = vo + at.

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  1. 24 October, 21:10
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    Answer: 27 m/s

    Explanation:

    vo = 15 m/s

    a = 2 m/s^2

    t = 6s

    v = vo + at

    v = 15 + 2 (6)

    v = 15 + 12

    v = 27 m/s
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