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2 June, 01:40

How much work would be needed to raise the payload from the surface of the moon (i. e., x = r) to the "end of the universe"?

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  1. 2 June, 01:44
    0
    W (3R) - W (2R) = - PR² (1 / (3R) - 1 / (2R)) = PR/6

    Explanation:

    "Assume the weight move up at constant speed. With no net acceleration, the force applied is - (weight). Since the weight at height R is - P (R/x) ² (minusbecause it's directed downward) the applied lifting force is P (R/x) ², and the work done moving from x to x+dx is dW = P (R/x) ² dx. Intetgrate this:"

    W (x) = ? PR²/x² dx = - PR²/x + C

    The work done moving from x=R to x=2R is:

    W (2R) - W (R) = - PR² (1 / (2R) - 1/R) = PR/2

    (b) The work done moving from 2R to 3R is:

    W (3R) - W (2R) = - PR² (1 / (3R) - 1 / (2R)) = PR/6
  2. 2 June, 01:47
    0
    Moon was rotation Earth or sun

    it's own orbit. universe is not end
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