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17 January, 01:54

Part complete during a collision with a wall, the velocity of a 0.200-kg ball changes from 20.0 m/s toward the wall to 12.0 m/s away from the wall. if the time the ball was in contact with the wall was 60.0 ms, what was the magnitude of the average force applied to the ball?

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  1. 17 January, 02:08
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    The average force applied to the ball = 106.7 N

    Explanation:

    Force is given by

    f = ΔP/t

    ΔP = change in momentum = m Vf - m Vi

    m = mass = 0.2 kg

    Vf = final velocity = 12 m/s

    Vi=initial velocity = - 20 m/s (negative because it is going towards the wall which is treated as negative axis)

    t = time = 60 ms = 0.06 s

    now ΔP = 0.2 [ 12 - (-20) ]

    ΔP=0.2 (32) = 6.4 kg m/s

    now force F = ΔP/t

    F = 6.4/0.06

    F=106.7 N
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