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1 February, 08:28

A 8.0 µF capacitor is initially connected to a 2.0 V battery. Once the capacitor is fully charged the battery is removed and a 6.0 Ω resistor is connected between the two terminals of the capacitor. Find the current flowing through the resistor 13.0 µsec after the capacitor begins to be discharged.

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  1. 1 February, 08:36
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    I = 0.451 amp

    Explanation:

    given,

    C = 8.0 µF

    V = 2 V

    resistor connected between two terminal = 6 Ω

    current flowing through resistor = 13 µsec

    Q = CV

    Q = 8 x 2

    Q = 16 µC

    for an RC discharge circuit

    V = V_0e^{-/dfrac{t}{RC}}

    I = / dfrac{-Q_0}{RC}e^{-/dfrac{t}{RC}}

    t = 13 µsec

    I = / dfrac{-16}{6/times 2}e^{-/dfrac{13}{6/times 2}}

    I = 0.451 amp

    neglecting - ve sign just to show direction.
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