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23 May, 04:35

A gas is compressed from an initial volume of 5.55 L to a final volume of 1.22 L by an external pressure of 1.00 atm. During the compression, the gas releases 124 J of heat. What is the change in the internal energy of the gas?

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  1. 23 May, 04:36
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    change in the volume of the gas = 5.55 - 1.22

    = 4.33 X 10⁻³ m³

    external pressure (constant) P = 1 x 10⁵ Pa

    work done on the gas

    =external pressure x change in volume

    = 10⁵ x 4.33 X 10⁻³

    =4.33 x 10²

    433 J

    Using the formula

    Q = ΔE + W, Q is heat added, ΔE is change in internal energy, W is work done by the gas

    Given

    Q = - 124 J (heat is released so negative)

    W = - 433 J. (work done by gas is negative, because it is done on gas)

    - 124 = ΔE - 433

    ΔE = 433 - 124

    = 309 J

    There is increase of 309 J in the internal energy of the gas.
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