A light bulb with resistance of 22 ohms is connected to a 110 V battery. What is the current

flowing through the circuit?

5A. The current that flowing through the circuit with a lightbulb of 22Ω connected to a voltage source of 110V is 5A.

The key to solve this problem is using Ohm's Law equations V = I*R, where V is the voltage drop, I is the current that flow through the element and R its resistance.

Clear I from the equation above:

I = V/R

With V = 110V, and R (lightbulb) = 22Ω

I = 110V/22Ω = 5A