Ask Question
22 March, 12:31

A water tank is in the shape of an inverted cone with depth 10 meters, and top radius 8 meters. Water is flowing into the tank at a rate of 0.1 cubic meters / min, but leaking out at a rate of 0.002h^20.002 h 2 cubic meters / min, where hh is the depth of water in the tank, in meters. Find the depth of water when the volume of water in the tank is neither increasing nor decreasing.

+2
Answers (1)
  1. 22 March, 12:44
    0
    The value of leaking rate in the question is repeated. By searching on the web I could find the correct value wich is 0.002h^2 m^3 / min.

    The depth of the water has to be equal to 7.07 m in order to have a stationary volume.

    Explanation:

    In order to have a stationary water level the flow of water that comes into the tank (0.1 m^3/min) must be equal to the flow of water that goes out of the tank (0.002*h^2 m^3/min), therefore:

    0.002*h^2 = 0.1

    h^2 = 0.1/0.002

    h^2 = 50

    h = sqrt (50) = 7.07 m
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A water tank is in the shape of an inverted cone with depth 10 meters, and top radius 8 meters. Water is flowing into the tank at a rate of ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers