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22 July, 19:43

When jumping, a flea accelerates at an astounding 1400 m/s2, but over only the very short distance of 0.55 mm. If a flea jumps straight up, and if air resistance is neglected (a rather poor approximation in this situation), how high does the flea go

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  1. 22 July, 19:45
    0
    0.079 m or 79 mm

    Explanation:

    Using the equation of motion

    v = √ (2as)

    Where v is the velocity

    a is acceleration = 1400m/s²

    s is the distance = 0.55 mm = 0.00055m

    Therefore

    = √ (2 * 1400m/s² * 0.00055 m) = 1.54 m/s

    Therefore; initial velocity = 1.54 m/s

    Then we use the equation of motion s = v² / 2g

    Take g = 9.8 m/s²

    Therefore

    = (1.54m/s) ² / 19.6 m/s²

    = 0.079 m or 79 mm
  2. 22 July, 19:54
    0
    Given:

    Acceleration, a = 1400 m/s^2

    Distance, s = 0.55 mm

    = 0.000055 m

    Final velocity, v = 0 m/s

    Using equation of motion,

    v^2 = u^2 + 2as

    u = √ (2as)

    = √ (2 * 1400 * 0.000055)

    = 0.8775 m/s

    Initial velocity, u = 0.8775 m/s

    Finding distance, S at, a = g = 9.8 m/s^2

    Using equations of motion above,

    S = u²/2g

    = (0.8775) ² / (2 * 9.8)

    = 0.039 m

    = 39 mm
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