If the result of your calculation of a quantity has si units kg•m^2/s^2•C, that quantity could be

It would be Joules.

Workdone is measured in Joules.

Workdone = Force * distance

Force = mass * acceleration

= kg * ms⁻²

= kgms⁻²

Distance = m

So, Force * distance

kgms⁻² * m

Apply laws of indices that says

x² * x³ = x²⁺³ = x⁵

Therefore, It would be kgm²s⁻²

m¹ * m¹ = m¹⁺¹ = m²

s⁻² is also = s / 2

Well, the " kg-m/s² " is a Newton ... that's a [force].

When it's multiplied by another 'm', you get " kg-m²/s² ".

That's [force] · [distance], which is [work] or [energy].

So far, we have [energy] / C.

If the 'C' stands for 'Coulomb' of charge, then the whole thing

is [energy] / [charge] or " joule / Coulomb ". That's a volt!

So the whole thing is a unit of electrical potential, potential difference,

or electromotive force.

When I first saw this question, I was trying hard to make it a unit

of something that has to do with heat, because I thought that big

' C ' out at the end was actually ' °C ' for Celsius degree. But I think

the electrical stuff is better. So that's my answer and I'm stickin' to it.