A 20-g bullet collides inelastically with a 3-kg wooden block at rest. After the collision, the bullet-block system moves with a speed vf = 1.5 m/s. How much kinetic energy is lost in the collision?

Question

Olivia Taylor

Physics

15 November, 17:43

A 20-g bullet collides inelastically with a 3-kg wooden block at rest. After the collision, the bullet-block system moves with a speed vf = 1.5 m/s. How much kinetic energy is lost in the collision?

+5

Answers (1)

Know the Answer?

Ayaan Mayer · Answer 1

I don't think it's possible to calculate it with the information given.

The kinetic energy after the collision is

(1/2) (mass) (speed) ²

= (1/2) (3kg + 20g) (1.5 m/s) ²

= (1.51 kg) (2.25 m²/s²)

= 3.3975 joules.

That's nice to know, but we can't tell how much there was before the

collision, because we don't know what the speed of the bullet was.