A 0.50kg object is at rest. A 3.00N force to the right acts on the objest during the time interval of 1.50s

Question

Nikki

Physics

12 February, 06:36

A 0.50kg object is at rest. A 3.00N force to the right acts on the objest during the time interval of 1.50s

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Answers (1)

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Chubs · Answer 1

The question you want to be answering is:

What is the velocity of the object at the end of this interval?

Key:

M=0.5kg

F=3N

Δt = 1.5s

Vi=0m/s

Formula:

F*Δt=m (Vf-Vi)

Plug it in

3 (1.5) = 0.5 (Vf-0)

Solve for Vf

4.5=0.5Vf

Vf = 9 m/s