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28 May, 02:44

A particle moves along the x axis. Its position as function of time is given by x=6.8t+8.5t^2, where t is in seconds and x is in meters. What is the acceleration as a function of time?

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  1. 28 May, 03:11
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    Displacement=x-0=x (assuming the journey started at t=0)

    time=t

    x=ut+1/2 at^2

    u=initial velocity=0

    acceleration=a = ((x-ut) * 2) / t^2

    a = (13.6t+17t^2) / t^2

    a=17+13.6/t
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