An early submersible craft for deep-sea exploration was raised and lowered by a cable from a ship. When the craft was stationary, the tension in the cable was 7000 N {/rm N}. When the craft was lowered or raised at a steady rate, the motion through the water added an 1800 N {/rm N} drag force. Part AWhat was the tension in the cable when the craft was being lowered to the seafloor? Express your answer to two significant figures and include the appropriate units. Part BWhat was the tension in the cable when the craft was being raised from the seafloor? Express your answer to two significant figures and include the appropriate units.

Question

Moriah

Physics

21 August, 17:00

An early submersible craft for deep-sea exploration was raised and lowered by a cable from a ship. When the craft was stationary, the tension in the cable was 7000 N {/rm N}. When the craft was lowered or raised at a steady rate, the motion through the water added an 1800 N {/rm N} drag force. Part AWhat was the tension in the cable when the craft was being lowered to the seafloor? Express your answer to two significant figures and include the appropriate units. Part BWhat was the tension in the cable when the craft was being raised from the seafloor? Express your answer to two significant figures and include the appropriate units.

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Answers (1)

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Kendra Lozano · Answer 1

When the craft was stationary, weight will be balanced by tension

T = mg

T = 7000 N

A)

when the craft was being lowered to the seafloor

drag force will act in upper direction, so

T₁ + 1800 = mg

T₁ = mg - 1800

= 7000 - 1800

= 5200 N

52 X 10² N

B)

when the craft was being raised from the seafloor, Tension will act in downward direction

T₂ = mg + 1800

T₂ = 7000 - 1800

= 8800N