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31 March, 01:42

Calculate the value of two equal charges if they repel one another with a force of 10 N having 10 m distance apart in a vacuum. What would be the size of the charges if they were situated in an insulting liquid whose permittivity was ten times that of a vacuum.

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  1. 31 March, 02:06
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    a) From Coulombs law,

    F = (kq1q2) / r² ... 1

    F = 10 N

    r = 10m

    k = 9 * 10^9 m/F

    q1 = q2

    from equation 1, make q the subject

    q = (Fr²) / 2k

    q = (10*10²) / (2*9*10^9)

    q = 1000/1.8*10^10

    q = 5.556*10^-8 C

    b) K = k/ko

    k = Kko = 10times permittivity of free-space

    Goodluck
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