A bumper car with a mass of 200 kilograms traveling at a velocity of 3.5 meters/second collides with a stationary bumper car with a mass of 250 kilograms. If the two bumper cars stick and move together at a velocity of 2.3 meters/second, what is the kinetic energy of the system after the collision

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15 September, 15:25

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Heaven Howard · Answer 1

Ek = (m·V²) / 2

V - velocity of system after the collision

m = m1 + m2

Ek = (m1 + m2) ·V²/2

Ek = (200 + 250) ·2,3²/2 = 450·5,29/2 = 1190,25 J