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13 March, 05:04

A 34-cm-tall, 6.0-cm-diameter cylindrical beaker is filled to its brim with water. What is the downward force of the water on the bottom of the beaker?

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  1. 13 March, 05:23
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    h = height of the beaker = 34 cm = 0.34 m

    ρ = density of water in the beaker = 1000 kg/m³

    g = acceleration due to gravity = 9.8 m/s²

    P₀ = atmospheric pressure = 101325 pa

    P = pressure at the bottom of the beaker

    Pressure at the bottom of the beaker is given as

    P = P₀ + ρ g h

    inserting the values

    P = 101325 + (1000) (9.8) (0.34)

    P = 104657 Pa

    d = diameter of cylindrical beaker = 6 cm = 0.06 m

    A = area of the bottom of the beaker = (0.25) πd² = (0.25) (3.14) (0.06) ² = 0.00283 m²

    Downward force of the water on the bottom of the beaker is given as

    F = PA

    F = (104657) (0.00283)

    F = 296.2 N
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