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28 December, 13:59

A baseball player swings his bat at a pitch and manages to hit it with a velocity of 60 mph as it leaves the bat. The ball has an initial angle of 55 degrees to the horizontal and he hits the ball at a vertical location 80 cm off the ground. How far horizontally (the "range") does the ball travel before before hits the ground?

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  1. 28 December, 14:29
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    The ball travels 27.15 m horizontally before hitting the ground.

    Explanation:

    Considering the vertical motion of baseball (upward positive), we need to find when it reaches the ground

    Initial velocity, u = 60 sin 55 = 49.15mph = 13.65 m/s

    Acceleration, a = - 9.81 m/s²

    Displacement, s = - 80 cm = - 0.8 m

    Substituting in s = ut + 0.5 at²

    -0.8 = 13.65 x t - 0.5 x 9.81 x t²

    4.905 t² - 13.65 t - 0.8 = 0

    t = 2.84 s or t = -.057 s (not possible)

    So the ball will hit ground after 2.84 s

    We need to find horizontal distance traveled during 2.84 seconds

    Initial velocity, u = 60 cos 55 = 34.41mph = 9.56 m/s

    Acceleration, a = 0 m/s²

    Time, t = 2.84

    Substituting in s = ut + 0.5 at²

    s = 9.56 x 2.84 + 0.5 x 0 x 2.84²

    s = 27.15 m

    The ball travels 27.15 m horizontally before hitting the ground.
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