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23 December, 14:00

A cell supplies a current of 0.6A through a 2 Ohms coil and a current of 0.2A through a 7 Ohms coil. Calculate the e. M. F. Of the cell.

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  1. 23 December, 14:02
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    E. M. F = 1.5 V

    Explanation:

    The equation relating EMF, internal resistance and external resistance is given by;

    E = Ir + IR

    Where; E is the EMF, I is the current, r is the internal resistance, and R is the external resistance.

    Therefore;

    When I = 0.6 A and R = 2Ω

    E = 0.6 r + (0.6 * 2)

    E = 0.6r + 1.2

    When I = 0.2 A and R = 7 Ω

    E = 0.2 r + (0.2 * 7)

    E = 0.2 r + 1.4

    Solving simultaneously;

    E = 0.6r + 1.2

    E = 0.2 r + 1.4; eliminating E

    0 = 0.4 r - 0.2

    0.4 r = 0.2

    r = 0.5

    Therefore;

    E = 0.2 (0.5) + 1.4

    = 0.1 + 1.4

    = 1.5 V
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