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19 April, 02:14

The specific heat of a certain type of metal is 0.128 J / (g⋅∘C).0.128 J / (g⋅∘C). What is the final temperature if 305 J305 J of heat is added to 94.0 g94.0 g of this metal, initially at 20.0 ∘C?

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  1. 19 April, 02:20
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    45.3°C

    Explanation:

    Heat gained = mass * specific heat * increase in temperature

    q = mC (T - T₀)

    Given C = 0.128 J/g/°C, m = 94.0 g, q = 305 J, and T₀ = 20.0°C:

    305 J = (94.0 g) (0.128 J/g/°C) (T - 20.0°C)

    T = 45.3°C
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