The radius of the planet saturn is 6.03 * 107 m, and its mass is 5.68 * 1026 kg.

a. find the density of saturn (its mass divided by its volume) in grams per cubic centimeter. (the volume of a sphere is given by πr 3.) 4 __3

b. find the surface area of saturn in square meters. (the surface area of a sphere is given by 4πr 2.)

You wouldn't know it from reading the question,

but the volume of a sphere is

4/3 π (radius) ³.

So the volume of Saturn is

(4/3 π) (6.03 x 10⁷ m) ³ = about 9.184 x 10²³ m³

and its density is (mass) / (volume)

= (5.68 x 10²⁶ kg) / (9.184 x 10²³ m³)

Sadly, we need this to be in units of ' gram/cm³ ' so we need to

account for some conversion of units.

= (5.68 x 10²⁶ kg) · (1,000 g/kg) / (9.184 x 10²³ m³) · (10⁶ cm³/m³)

= (5.68 x 10²⁹ grams) / (9.184 x 10²⁹ cm³)

= 0.618 gram/cm³.

Look at that!

The density of the planet Saturn is less than ' 1 '.

If you had a big enough bathtub full of water, Saturn would float in it!

The surface area of a sphere is

4 π (radius) ²

= (4 π) (6.03 x 10⁷ m) ²

= (4 π) (36.4 x 10¹⁴ m²)

= 4.57 x 10¹⁶ m²

I hope it cleared your doubt.