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23 July, 00:21

a wire with mass per unit length 75 g/m runs horizontally at right angles to a uniform horizontal 0.12 T magnetic field. what amount of current must flow through the wire for it to be suspended against gravity by magnetic force

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  1. 23 July, 00:40
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    The amount of current that must flow through the wire for it to be suspended against gravity by magnetic force = 6.125 A

    Explanation:

    Force on a wire carrying current in an electric field is given by

    F = (B) (I) (L) sin θ

    For this question,

    The magnetic force must match the weight of the wire.

    F = mg

    mg = (B) (I) (L) sin θ

    (m/L) g = (B) (I) sin θ

    Mass per unit length = 75 g/m = 0.075 kg/m

    B = magnetic field = 0.12 T

    I = ?

    g = acceleration due to gravity = 9.8 m/s

    θ = angle between wire's current direction and magnetic field = 90°

    0.075 * 9.8 = 0.12 * I sin 90°

    I = 0.075 * 9.8/0.12 = 6.125 A
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