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14 April, 06:33

A 92.0-kg skydiver falls straight downward with an open parachute through a vertical height of 325 m. The skydiver's velocity remains constant. What is the work done by the nonconservative force of air resistance, which is the only nonconservative force acting?

A) + 2.93 times 10^5 J

B) 0J

C) Answer is not obtainable, because insufficient information about the skydiver's speed is given.

D) - 2.93 times 10^5 J

+5
Answers (1)
  1. 14 April, 06:44
    0
    The answer is A

    Explanation:

    Work done = mgh

    where mass, m = 92kg, g = 9.81, height, h = 325m

    Therefore,

    W = mgh

    W=92*9.81*325

    W=293319

    W=2.93*10>5
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