A 92.0-kg skydiver falls straight downward with an open parachute through a vertical height of 325 m. The skydiver's velocity remains constant. What is the work done by the nonconservative force of air resistance, which is the only nonconservative force acting?

A) + 2.93 times 10^5 J

B) 0J

C) Answer is not obtainable, because insufficient information about the skydiver's speed is given.

D) - 2.93 times 10^5 J

Question

Israel Richmond

Physics

14 April, 06:33

A 92.0-kg skydiver falls straight downward with an open parachute through a vertical height of 325 m. The skydiver's velocity remains constant. What is the work done by the nonconservative force of air resistance, which is the only nonconservative force acting?

A) + 2.93 times 10^5 J

B) 0J

C) Answer is not obtainable, because insufficient information about the skydiver's speed is given.

D) - 2.93 times 10^5 J

+5

Answers (1)

Know the Answer?

Maddox Bush · Answer 1

The answer is A

Explanation:

Work done = mgh

where mass, m = 92kg, g = 9.81, height, h = 325m

Therefore,

W = mgh

W=92*9.81*325

W=293319

W=2.93*10>5