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18 June, 04:19

old stars obtain part of their energy by the fusion of three alpha particles to form a 12/6c nucleus, whose mass is 12.0000 u. How much energy is given off in each such reaction?

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  1. 18 June, 04:29
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    11.6532 x 10⁻¹¹ J or 7.3 MeV is given off

    Explanation:

    Mass of an alpha particle = 4.0026u, ∴ mass of three = 12.0078u

    Find the difference in mass.

    Mass of three alpha - Mass of Carbon nucleus

    12.0078u - 12u = 0.0078u

    Since 1u = 1.66 x 10⁻²⁷ kg

    Therefore, 0.0078u = 1.2948 x 10⁻²⁷

    Now that we know Mass (m) = 1.2948 x 10⁻²⁷ and Speed (c) 3 x 10⁸ m²s⁻²

    Formular for Energy = => E₀ = mc²

    E = (1.2948 x 10⁻²⁷) (3 x 10⁸ m²s⁻²) ²

    E = (1.2948 x 10⁻²⁷) (9 x 10¹⁶) J

    E = 11.6532 x 10⁻¹¹ J

    Or, if you need your energy in MeV

    1 MeV = 1.60x10⁻¹³ J

    Just do the conversion by dividing 11.6532 x 10⁻¹¹ J by 1.60x10⁻¹³ J

    It will give you 7.3 MeV
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