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3 October, 00:26

How much heat is needed to raise the temperature of 100.0 g of water by 50.0°C? (Water's specific heat is 4.18 J/g•°C)

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  1. 3 October, 00:30
    0
    20900 J

    Explanation:

    Formula:Q=m*c*△θ m=100g c=4.18 △θ=50°C Q=100*4.18*50=20900J
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