A certain brand of hot dog cooker works by applying a potential difference of 120 V across opposite ends of a hot dog and allowing it to cook by means of the thermal energy produced. The current is 11.5 A, and the energy required to cook one hot dog is 59.0 kJ. If the rate at which energy is supplied is unchanged, how long will it take to cook three hot dogs simultaneously?

Question

Proctor

Physics

27 July, 19:41

A certain brand of hot dog cooker works by applying a potential difference of 120 V across opposite ends of a hot dog and allowing it to cook by means of the thermal energy produced. The current is 11.5 A, and the energy required to cook one hot dog is 59.0 kJ. If the rate at which energy is supplied is unchanged, how long will it take to cook three hot dogs simultaneously?

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Answers (1)

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Rebel · Answer 1

Answer: 43s

Explanation:

The stored energy across a plate can be measured by calculating the electric charge and the potential difference. Also, the quantity of electricity can be measured by multiplying the current in the circuit with the time taken.

Given

Potential difference, V = 120 v

Current, I = 11.5 A

Energy, E = 59 kJ

Remember,

E = QV, so that

Q = E/V

Q = 59000/120

Q = 491.67 C

Q = IT

491.67 = 11.5*t

t = 491.67/11.5

t = 42.75s ~ 43s

Time taken to cook the 3 hot dogs simultaneously is 43s