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19 February, 22:31

A force of 45 newtons is applied on an object, moving it 12 meters away in the same direction as the force. What is the magnitude of work done on the object by this force?

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  1. 19 February, 22:58
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    If the applied force is in the same direction as the object's displacement, the work done on the object is:

    W = Fd

    W = work, F = force, d = displacement

    Given values:

    F = 45N

    d = 12m

    Plug in and solve for W:

    W = 45 (12)

    W = 540J
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